1/x+1+3/x^2-4=2/2x-x

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Solution for 1/x+1+3/x^2-4=2/2x-x equation: 



1/x+1+3/x^2-4=2/2x-x

We move all terms to the left:

1/x+1+3/x^2-4-(2/2x-x)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R





Domain of the equation: 2x-x)!=0

x∈R



We add all the numbers together, and all the variables

1/x+3/x^2-(-1x+2/2x)+1-4=0

We add all the numbers together, and all the variables

1/x+3/x^2-(-1x+2/2x)-3=0

We get rid of parentheses

1/x+3/x^2+1x-2/2x-3=0

We calculate fractions

We do not support expression: x^4

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